F(3)=x^2+2.3x-9

Solution for F(3)=x^2+2.3x-9 equation:

(3)=F^2+2.3F-9

We move all terms to the left:

(3)-(F^2+2.3F-9)=0

We get rid of parentheses

-F^2-2.3F+9+3=0

We add all the numbers together, and all the variables

-1F^2-2.3F+12=0

a = -1; b = -2.3; c = +12;
Δ = b2-4ac
Δ = -2.32-4·(-1)·12
Δ = 53.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.3)-\sqrt{53.29}}{2*-1}=\frac{2.3-\sqrt{53.29}}{-2}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.3)+\sqrt{53.29}}{2*-1}=\frac{2.3+\sqrt{53.29}}{-2}
$